Java Lambda Expressions
Java Lambda Expressions
Java lambda expressions are new in Java 8. Java lambda expressions are Java's first step into functional programming. A Java lambda expression is thus a function which can be created without belonging to any class. A lambda expression can be passed around as if it was an object and executed on demand.
Java Lambdas and the Single Method Interface
Functional programming is very often used to implement event listeners. Event listeners in Java are often defined as interfaces with a single method on. Here is a fictive single method interface example:
public interface StateChangeListener { public void onStateChange(State oldState, State newState); }
This interface defines a single method which is called whenever the state changes (in whatever is being observed).
In Java 7 you would have to implement this interface in order to listen for state changes. Imagine you have a class called
StateOwner
which can register state event listeners. Here is an example:public class StateOwner { public void addStateListener(StateChangeListener listener) { ... } }
In Java 7 you could add an event listener using an anonymous interface implementation, like this:
StateOwner stateOwner = new StateOwner(); stateOwner.addStateListener(new StateChangeListener() { public void onStateChange(State oldState, State newState) { // do something with the old and new state. } });
First a
StateOwner
instance is created. Then an anonymous implementation of theStateChangeListener
interface is added as listener on the StateOwner
instance.
In Java 8 you can add an event listener using a Java lambda expression, like this:
StateOwner stateOwner = new StateOwner(); stateOwner.addStateListener( (oldState, newState) -> System.out.println("State changed") );
The lambda expressions is this part:
(oldState, newState) -> System.out.println("State changed")
The lambda expression is matched against the parameter type of the
addStateListener()
method's parameter. If the lambda expression matches the parameter type (in this case theStateChangeListener
interface) , then the lambda expression is turned into a function that implements the same interface as that parameter.
Lambda expressions can only be used where the type they are matched against is a single method interface. In the example above, a lambda expression is used as parameter where the parameter type was the
StateChangeListener
interface. This interface only has a single method. Thus, the lambda expression is matched successfully against that interface.Matching Lambdas to Interfaces
A single method interface is also sometimes referred to as a functional interface. Matching a Java lambda expression against a functional interface is divided into these steps:
- Does the interface have only one method?
- Does the parameters of the lambda expression match the parameters of the single method?
- Does the return type of the lambda expression match the return type of the single method?
If the answer is yes to these three questions, then the given lambda expression is matched successfully against the interface.
Lambda Type Inference
Before Java 8 you would have to specify what interface to implement, when making anonymous interface implementations. Here is the example from the beginning of this text:
stateOwner.addStateListener(new StateChangeListener() { public void onStateChange(State oldState, State newState) { // do something with the old and new state. } });
With Lambda expressions the type can often be inferred from the surrounding code. For instance, the interface type of the parameter can be inferred from the method declaration of the
addStateListener()
method (the single method on the StateChangeListener
interface). This is called type inference. The compiler infers the type of a parameter by looking elsewhere for the type - in this case the method definition. Here is the example from the beginning of this text, showing that theStateChangeListener
interface is not mentioned in the lambda expression:stateOwner.addStateListener( (oldState, newState) -> System.out.println("State changed") );
In the lambda expression the parameter types can often be inferred too. In the example above, the compiler can infer their type from the
onStateChange()
method declaration. Thus, the type of the parameters oldState
and newState
are inferred from the method declaration of theonStateChange()
method.Lambda Parameters
The
(oldState, newState)
part of the lambda expression shown earlier specifies the parameters the lambda expression takes. These parameters have to match the parameters of the method on the single method interface. In this case, these parameters have to match the parameters of theonStateChange()
method of the StateChangeListener
interface:public void onStateChange(State oldState, State newState);
As a minimum the number of parameters in the lambda expression and the method must match.
Second, if you have specified any parameter types in the lambda expression, these types must match too. I haven't shown you how to put types on lambda expression parameters yet (I will add that to this tutorial soon), but in many cases you don't need them.
Zero Parameters
If the method you are matching your lambda expression against takes no parameters, then you can write your lambda expression like this:
() -> System.out.println("Zero parameter lambda");
Notice how the parentheses have no content in between. That is to signal that the lambda takes no parameters.
One Parameter
If the method you are matching your lambda expression against takes one parameter, you can write the lambda expression like this:
(param) -> System.out.println("One parameter: " + param);
Notice the parameter is listed inside the parentheses.
When a lambda expression takes a single parameter, you can also omit the parentheses, like this:
param -> System.out.println("One parameter: " + param);
Multiple Parameters
If the method you match your lambda expression against takes multiple parameters, the parameters need to be listed inside parentheses. Here is how that looks:
(p1, p2) -> System.out.println("Multiple parameters: " + p1 + ", " + p2);
Only when the method takes a single parameter can the parentheses be omitted.
Parameter Types
Specifying parameter types for a lambda expression may sometimes be necessary if the compiler cannot infer the parameter types from the functional interface method the lambda is matching. Don't worry, the compiler will tell you when that is the case. Here is a Java lambda parameter type example:
(Car car) -> System.out.println("The car is: " + car.getName());
As you can see, the type (
Car
) of the car
parameter is written in front of the parameter name itself, just like you would when declaring a parameter in a method elsewhere, or when making an anonymous implementation of an interface.Lambda Function Body
The body of a lambda expression, and thus the body of the function / method it represents, is specified to the right of the
->
in the lambda declaration: Here is an example:(oldState, newState) -> System.out.println("State changed")
If your lambda expression needs to consist of multiple lines, you can enclose the lambda function body inside the
{ }
we also use when declaring methods elsewhere. Here is an example:(oldState, newState) -> { System.out.println("Old state: " + oldState); System.out.println("New state: " + newState); }
Returning a Value From a Lambda Expression
You can return values from lambda expressions, just like you can from a method. You just add a return statement to the lambda function body, like this:
(param) -> { System.out.println("param: " + param); return "return value"; }
In case all your lambda expression is doing is to calculate a return value and return it, you can specify the return value in a shorter way. Instead of this:
(a1, a2) -> { return a1 > a2; }
You can write:
(a1, a2) -> a1 > a2;
The compiler then figures out that the expression
a1 > a2
is the return value of the lambda expression (hence the name lambda expressions).Lambdas as Objects
A Java lambda expression is essentially an object. You can assign a lambda expression to a variable and pass it around, like you do with any other object. Here is an example:
public interface MyComparator { public boolean compare(int a1, int a2); }
MyComparator myComparator = (a1, a2) -> return a1 > a2; boolean result = myComparator.compare(2, 5);
The first code block shows the interface which the lambda expression implements. The second code block shows the definition of the lambda expression, how the lambda expression is assigned to variable, and finally how the lamdba expression is invoked by invoking the interface method it implements.
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